Y=-3x^2+5x-10

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Solution for Y=-3x^2+5x-10 equation: 



=-3Y^2+5Y-10

We move all terms to the left:

-(-3Y^2+5Y-10)=0

We get rid of parentheses

3Y^2-5Y+10=0

a = 3; b = -5; c = +10;
Δ = b2-4ac
Δ = -52-4·3·10
Δ = -95
Delta is less than zero, so there is no solution for the equation

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